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Human Jump • Mass: 70 kg • v₀ ≈ 6 m/s

Projectile Motion & Trajectory for a Human Jump

Analyzing the 2D parabolic flight path of a standard Human Jump (mass 70 kg).An athletic running long jump or gymnastics vault takeoff.

Trajectory curves and apex altitudes are modeled in real-time on the HTML5 canvas below using classical two-dimensional kinematic equations (R = v²·sin(2θ)/g).

Projectile Motion & Parabolic Trajectory

Classical 2D Kinematics in Vacuum (Halliday & Resnick)

R = (v² · sin(2θ)) / g | H_max = (v² · sin²(θ)) / (2g) | T = (2v · sin(θ)) / g
Launch Velocity (v₀)6 m/s
1 m/s22 km/h100 m/s
Launch Angle (θ)45°
5° (Flat)45° (Max Range)85° (Vertical)
Object Presets:
Parabolic Flight Trajectory
Apex: 0.9mImpact: 3.7m
Horizontal Range (R)
3.67 m

Total horizontal distance traveled until impact.

Maximum Height (H_max)
0.92 m

Peak vertical altitude at trajectory apex.

Flight Hang Time (T)
0.86 s

Total airborne duration from launch to ground.

Human Jump Flight Metrics Across Launch Angles (v₀ = 6 m/s)

Launch Angle (θ)Range (R)Max Apex Height (H_max)Flight Duration (T)Trajectory Type
15°
1.84 m0.12 m0.32 sFlat Drive / Low Line
30°
3.18 m0.46 m0.61 sOptimal Balistic Arc
45°Max Range
3.67 m0.92 m0.87 sOptimal Balistic Arc
60°
3.18 m1.38 m1.06 sOptimal Balistic Arc
75°
1.84 m1.71 m1.18 sHigh Lob / Pop-up

Explore Other Kinematics & Motion Calculators

Frequently Asked Questions

Q1.What launch angle provides maximum range for a Human Jump?

In a vacuum (or neglecting air resistance), maximum horizontal range for any projectile is achieved at an exact launch angle of 45°, where sin(2θ) = 1. At 6 m/s, the theoretical maximum range is 3.7 meters.

Q2.Does the 70kg mass of the Human Jump alter its parabolic trajectory?

In idealized classical kinematics without atmospheric drag, trajectory is strictly governed by initial velocity v₀, launch angle θ, and gravitational acceleration g—completely independent of mass. In real air, drag and Magnus spin force introduce minor deviations.

Q3.How long is a Human Jump in the air at 6 m/s and 45°?

Airborne hang time is calculated using T = 2v₀ · sin(θ) / g. For 6 m/s at 45°, flight duration is 0.87 seconds.

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