Braking & Stopping Distance at 10 km/h
Traveling at 10 km/h (equivalent to 2.8 meters per second), an average passenger vehicle requires a total stopping distance of 4.7 meters on dry asphalt and 5.2 meters on wet roads under standard AASHTO 1.5-second reaction time assumptions.
Total stopping distance combines the distance covered during driver perception/reaction (d_reaction = v · t_react) with the physical skid/braking distance (d_braking = v² / (2μg)).
Automotive Braking & Total Stopping Distance
AASHTO Geometric Highway Design & Newtonian Friction Model
Distance traveled during 1.5s before pressing the brake pedal.
Tire friction work required to dissipate kinetic energy (v²/(2μg)).
Stopping Distance at 10 km/h Across Road Conditions
| Road Surface | Friction (μ) | Reaction Dist | Braking Dist | Total Stopping Dist | Car Lengths |
|---|---|---|---|---|---|
Dry Asphalt | μ = 0.7 | 4.2 m | 0.6 m | 4.7 m | ≈ 1.1 cars |
Wet Asphalt (Rain) | μ = 0.4 | 4.2 m | 1.0 m | 5.2 m | ≈ 1.1 cars |
Packed Snow | μ = 0.2 | 4.2 m | 2.0 m | 6.1 m | ≈ 1.4 cars |
Black Ice / Glaze | μ = 0.1 | 4.2 m | 3.9 m | 8.1 m | ≈ 1.8 cars |
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Frequently Asked Questions
Q1.What is the total stopping distance at 10 km/h on dry pavement?
At 10 km/h on dry asphalt (friction coefficient μ = 0.7) with an average 1.5-second driver reaction time, total stopping distance is 4.7 meters (4.2m perception/reaction + 0.6m physical braking).
Q2.How does wet weather or rain affect stopping distance at 10 km/h?
On wet roads (μ ≈ 0.4), physical braking distance increases from 0.6m to 1.0m, extending the total stopping distance by nearly 50%.
Q3.Why does stopping distance increase faster than speed?
Braking distance is proportional to the square of velocity (v²). Because kinetic energy is E = ½mv², doubling your speed requires four times as much frictional work to bring the vehicle to a complete stop.
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